0,01x^2+200x=0

Solution for 0,01x^2+200x=0 equation:

0.01x^2+200x=0

a = 0.01; b = 200; c = 0;
Δ = b2-4ac
Δ = 2002-4·0.01·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-200}{2*0.01}=\frac{-400}{0.02}
=-20000
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+200}{2*0.01}=\frac{0}{0.02}
=0
$